190.5=b^2*1.5

Solution for 190.5=b^2*1.5 equation:

190.5=b^2*1.5

We move all terms to the left:

190.5-(b^2*1.5)=0

We get rid of parentheses

-b^2*1.5+190.5=0

Wy multiply elements

-1.5b^2+190.5=0

a = -1.5; b = 0; c = +190.5;
Δ = b2-4ac
Δ = 02-4·(-1.5)·190.5
Δ = 1143
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1143}=\sqrt{9*127}=\sqrt{9}*\sqrt{127}=3\sqrt{127}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-3\sqrt{127}}{2*-1.5}=\frac{0-3\sqrt{127}}{-3}
=-\frac{3\sqrt{127}}{-3}
=-\frac{\sqrt{127}}{-1}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+3\sqrt{127}}{2*-1.5}=\frac{0+3\sqrt{127}}{-3}
=\frac{3\sqrt{127}}{-3}
=\frac{\sqrt{127}}{-1}
$